IBM IBM Specialist A2090-545

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IBM A2090-545 Exam Syllabus Topics:

IBM Assessment: DB2 9.7 SQL Procedure Developer Sample Questions:

Question 1

Given the following code

What would be value of parm2 if the following proc1 called as call proc1(3, ?)?

A. 8
B. 3
C. 0
D. 10

Question 2

Which of the following statements is true?

A. A DATETIME value can be assigned to a DATE variable.
B. Values cannot be assigned to variables inside ERROR HANDLERS.
C. A TIMESTAMP value can be assigned to a TIME variable.
D. The result of a GET DIAGNOSTICS statement cannot be assigned to a variable.

Question 3

Which of the following is the simplest way to define a record with fields corresponding to all of the columns that are fetched from a cursor or cursor variable?

A. Using the READ FROM CURSOR attribute
B. Using the VARRAY attribute
C. Using the %ROWTYPE attribute
D. Using the %CURSOR attribute

Question 4

In a SQL Procedure, rows_fetched is an integer variable and curEmp is a cursor variable of SELECT statement on a table. After opening the cursor curemp, which of the statement will determine the number of rows fetched?

A. SET rows_fetched = CURSOR_ROWCOUNT(curemp)
B. SET rows_fetched = curEmp%CURSOR_ROWCOUNT
C. SET rows_fetched = curEmp%ROWCOUNT
D. SET rows_fetched = ROWCOUNT(curemp)

Question 5

Using Optimistic Locking, both Transaction 1 and Transaction 2 have read the same row including the RID_BIT and ROW CHANGE TOKEN values. Transaction 1 updates the row after ensuring that the row has not changed after the previous SELECT by adding a RID_BIT and ROW CHANGE TOKEN predicate to the UPDATE statement. Transaction 2 now tries to update that same row using the same predicate as transaction 1. What will be the result?

A. The row will not be found because the value of the ROW CHANGE TOKEN has changed in regard to the UPDATE of transaction 1. Transaction 2 will complete with an insert of a new row.
B. The row will be found with a different ROW CHANGE TOKEN and Transaction 2 will overwrite the values set in transaction 1.
C. The row will not be found because the value of the ROW CHANGE TOKEN has changed in regard to the UPDATE of transaction 1. Transaction 2 has to retry in order to retrieve the current data.
D. The row will be found with the same ROW CHANGE TOKEN. Transaction 2 will now insert its values replacing those of transaction 1.

Solutions: